Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q551. |
|
| 1) | 6 | 2) | 10 |
| 3) | 12 | 4) | 20 |
| 5) | None of thse | ||
Answer : 20
Explanation :
Explanation :
Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.
The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.
The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.
So, required number of numbers = (1 x 5 x 4) = 20.
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Q552. |
|
| 1) | 810 | 2) | 1440 |
| 3) | 2880 | 4) | 50400 |
| 5) | 57600 | ||
Answer : 50400
Explanation :
Explanation :
In the word 'CORPORATION', we consider the vowels OOAIO as one letter.
Thus, we have CRPRTN (OOAIO).
This has 7 (6 + 1) letters of which R occurs 2 times and the rest are different.
Number of ways arranging these letters =7!/2! = 2520.
Now, 5 vowels in which O occurs 3 times and the rest are different, can be arranged in 5!/3!= 20 ways.
So, required number of ways = (2520 x 20) = 50400.
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Q553. |
|
| 1) | 360 | 2) | 480 |
| 3) | 720 | 4) | 1280 |
| 5) | None of these | ||
Answer : 720
Explanation :
Explanation :
The word 'LEADING'' has 7 different letters.
When the vowels EAI are always together, they can be supposed to form one letter.
Then, we have to arrange the letters LNDG (EAI).
Now, 5 (4 + 1 = 5) letters can be arranged in 5! = 120 ways.
The vowels (EAI) can be arranged among themselves in 3! = 6 ways.
So, required number of ways = (120 x 6) = 720.
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Q554. |
|
| 1) | 565 | 2) | 664 |
| 3) | 742 | 4) | 756 |
| 5) | None of these | ||
Answer : 756
Explanation :
Explanation :
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Q555. |
|
| 1) | Rs. 4462.50 | 2) | Rs. 8032.50 |
| 3) | Rs. 8900 | 4) | Rs. 8925 |
| 5) | None of these | ||
Answer : Rs. 8925
Explanation :
Explanation :
Principal = (100 x 4016.25 ) / ( 9 x 5) = Rs. 8925.
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Q556. |
|
| 1) | Rs. 650 | 2) | Rs. 690 |
| 3) | Rs. 698 | 4) | Rs. 700 |
| 5) | None of these | ||
Answer : Rs. 698
Explanation :
Explanation :
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
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Q557. |
|
| 1) | Rs. 800 | 2) | Rs. 900 |
| 3) | Rs. 1100 | 4) | Rs. 870 |
| 5) | None of these | ||
Answer : Rs. 900
Explanation :
Explanation :
Let the sum lent at 8% be Rs. x and that at 6% be
Rs. (1550 - x).
or (X x 8 x 1/100 ) + [ {(1500- X) x 6 x 1}/ 100 ] = 106
or 8 x + 9300 - 6 x = 10600
or 2 x = 1300
or x = 650
Money lent at 8% = Rs.650.
Money lent at 6% = Rs(1550 - 650) = Rs. 900
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Q558. | A sum was put at S.I. at certain rate for 5 years. Had it been put at 4% higher rate, it would have fetched Rs. 60 more. What was the sum ? |
| 1) | Rs.280 | 2) | Rs.300 |
| 3) | Rs.320 | 4) | Rs.400 |
| 5) | None of these | ||
Answer : Rs.300
Explanation :
Explanation :
Let Principal =P, Rate of Interest = R
Given, T = 5 So, (P x 5 x R) / 100
Now new rate of interest =( R+ 4) %
So, S.I. = {P x 5 x (R+ 5%) } / 100
Then, {P x 5 x (R+ 5%) } / 100 - (P x 5 x R) / 100 = 60
or P /60 = 5 or P= Rs. 300
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Q559. |
|
| 1) | 12 min | 2) | 15 min |
| 3) | 18 min | 4) | 20 min |
| 5) | None of these | ||
Answer : 15 min
Explanation :
Explanation :
Let pipe A fills the cistern in x minutes.
Therefore, pipe B will fill the cistern in (x + 5) minutes.
1/x + 1/x+1 = 1/6
or x = 10
Hence pipe B can fill the cistern in 10 +5 = 15 min.
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Q560. |
|
| 1) | 40 hours | 2) | 42 hours |
| 3) | 43 hours | 4) | 45 hours |
| 5) | None of these | ||
Answer : 42 hours
Explanation :
Explanation :
Resultant work done by both the pipes in one hour i.e. (1/6 + 1/7) = 1/42
of cistern.
The whole cistern will be emptied in 42 hours.
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