Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q1. |
|
1) | Rs.10,480 | 2) | Rs.11,240 |
3) | Rs.11,520 | 4) | Rs.12,420 |
5) | None of these |
Answer : Rs.11,520
Explanation :
Explanation :
Let the width of the rectangle = x m
Then, 250% of x = 40
x = 40 × 100/250 = 16 m
Perimeter of the rectangle = 2(length + width) = 2 × (40 + 16) = 112 cm
Perimeter of the square = (112 + 16) = 128 m
The sides of the square = 128/4 = 32 m
The area of the square field without street = (32)2 sq. cm = 1024 sq. m
The area of the square field with street = (32 + 8)2 sq. cm = 1600 sq. m
The area of the street = 1600 - 1024 = 576 sq. m
The total cost of constructing the street = 576 × 20 = Rs.11,520

Q2. | The length of a rectangle increases by 20% and also its breadth increases by 15% . What should be the percentage change in its perimeter? |
1) | 35% | 2) | 36% |
3) | 38% | 4) | Can't be determined |
5) | None of these |
Answer : Can't be determined

Q3. |
|
1) | 100.8 sq cm | 2) | 112.4 sq cm |
3) | 104.2 sq cm | 4) | Cannot be determined |
5) | None of these |
Answer : 100.8 sq cm

Q4. | The ratio of the adjacent angles of a parallelogram is 7 : 8. Also, the ratio of the angles of quadrilateral is 5 : 6 : 7 : 12. What is the sum of the smaller angle of the parallelogram and the second largest angle of the quadrilateral ? |
1) | 136° | 2) | 156° |
3) | 168° | 4) | 208° |
5) | None of these |
Answer : 168°
Explanation :
Explanation :
Sum of the adjacent angles of a parallelogram is 180°.
Smaller angle of the parallelogram = 7/15 × 180 = 84°
Second largest angle of the quadrilateral = 7/30 × 360 = 84°
Required sum = 84 + 84 = 168°

Q5. | The smallest side of a right-angled triangle is 8 cm less than the side of a square of perimeter 56 cm. The second largest side of the right-angled triangle is 4 cm less than the length of the rectangle of area 96 sq cm and breadth 8 cm. What is the largest side of the right-angled triangle ? |
1) | 10 cm | 2) | 12 cm |
3) | 15 cm | 4) | 18 cm |
5) | None of these |
Answer : 10 cm
Explanation :
Explanation :
Side of the square = 56/4 = 14 cm
smallest side of the triangle = 14 – 8 = 6 cm
Length of the rectangle = 96/ 8 = 12 cm
Second largest side of the triangle = 112 – 4 = 8 cm
So, Largest side of the triangle = square root of 62 + 82 = 10 cm

Q6. |
|
1) | 1/3 | 2) | 1/4 |
3) | 1/2 | 4) | No change |
5) | None of these |
Answer : 1/2
Explanation :

Explanation :
Let the length and breadth of the rectangle be L and B respectively.
Area = L x B = LB


Q7. |
|
1) | 25 | 2) | 36 |
3) | 38 | 4) | 30 |
5) | None of these |
Answer : 36
Explanation :
Explanation :
The smallest angle = 3/15 x 180° = 36°
The largest angle =7/15 x 180° = 84°
So, (36 x 2) - (84/ 2) = 36

Q8. |
|
1) | 344.35 cm2 | 2) | 462 cm2 |
3) | 498.35 cm2 | 4) | 456cm2 |
5) | None of these |
Answer : 498.35 cm2
Explanation :
Explanation :


Q9. |
|
1) | 18.8 cm | 2) | 23.5 cm |
3) | 24 cm | 4) | 31.3cm |
5) | None of these |
Answer : 24 cm
Explanation :
Explanation :
The final ratio of the triangle are 20 : 15 : 12
Perimeter = 20x + 15x + 12x = 47 x
So, 47x = 94
or = x = 2
Thus smallest side = 122 = 24 cm.

Q10. |
|
1) | 16 cm | 2) | 18 cm |
3) | 24 cm | 4) | Data Inadequate |
5) | None of these |
Answer : 18 cm
Explanation :
Explanation :
2(l + b) /b = 5/1 or 2l + 2b = 5b
or 3b = 2l b =2l/3
Then, Area = 216 cm2
l x b = 216
l x2l/3 = 216 or l2 = 324
or l = 18 cm.
