Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q1. |
|
1) | 456 km | 2) | 482 km |
3) | 548 km | 4) | 552 km |
5) | None of these |
Answer : 552 km
Explanation :
Explanation :
Given, the first term, a = 35, common difference, d = 2 and total number of terms, (n) = 12.
The sum of this series will be the total distance travelled.
Sum, Sn= n/2[2a + (n - 1) d] = 6 [70 + 11 x 2] = 552 km.

Q2. |
|
1) | 1 : 3 | 2) | 3 : 2 |
3) | 3 : 4 | 4) | Data Inadequate |
5) | None of these |
Answer : 3 : 2
Explanation :
Explanation :
Let, the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres, and length of the second train = 17y metres.
27x + 17y = 23 (x+ y)
or 27x + 17y = 23x + 23y
or 4x = 6y
or x/y = 3/2

Q3. |
|
1) | 230 m | 2) | 240 m |
3) | 260 m | 4) | 320 m |
5) | None of these |
Answer : 230 m
Explanation :

Explanation :


Q4. |
|
1) | 40 sec | 2) | 42 sec |
3) | 45 sec | 4) | 48 sec |
5) | None of these |
Answer : 40 sec
Explanation :

Explanation :


Q5. |
|
1) | 1 : 3 | 2) | 3 : 2 |
3) | 3 : 4 | 4) | 4 : 3 |
5) | None of these |
Answer : 3 : 2
Explanation : Let, the speeds of the two trains be x m/sec and y m/sec respectively.

Explanation : Let, the speeds of the two trains be x m/sec and y m/sec respectively.


Q6. |
|
1) | 45 km/hr | 2) | 50 km/hr |
3) | 54 km/hr | 4) | 55 km/hr |
5) | None of these |
Answer : 50 km/hr
Explanation : Given, 
Explanation : Given,


Q7. |
|
1) | 10 | 2) | 12 |
3) | 15 | 4) | 20 |
5) | None of these |
Answer : 12
Explanation : Given,
Explanation : Given,


Q8. |
|
1) | 200 m | 2) | 225 m |
3) | 245 m | 4) | 250 m |
5) | None of these |
Answer : 245 m
Explanation :
Explanation :
Given,


Q9. |
|
1) | 230 m | 2) | 240 m |
3) | 260 m | 4) | 270 m |
5) | None of these |
Answer : 240 m
Explanation : Given,
Explanation : Given,


Q10. |
|
1) | 220km | 2) | 240km |
3) | 250 km | 4) | 260 km |
5) | None of these |
Answer : 240km
Explanation : The first train after 2hours covers a distance 40 x 2 = 80 kms.
Explanation : The first train after 2hours covers a distance 40 x 2 = 80 kms.
Then, the second train starts and time for both trains is same .
According to relative speed formula, the relative speed in same direction = 60 - 40 =20kmph
So, time taken to cover the 80km = 80/20= 4 hrs
Therefore, the total distance = 60 x 4 = 240kms.
