Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q1. | A tank has leak which would empty the completely filled tank in 10 hours.If the tank is full of water and a tap is opened which admits 4 liters of water per minute in the tank, the leak takes 15 hours to empty the tank. How many liters of water does the tank hold ? |
1) | 2400 | 2) | 3600 |
3) | 4800 | 4) | 7200 |
5) | None of these |
Answer : 7200
Explanation : Let, the capacity of the tank be "X" liters.
Explanation : Let, the capacity of the tank be "X" liters.
According to the problem: 15 x (X/10 - 4 x 60) = X
Or X = 7200 liters

Q2. | A tank has three drain pipes, the first two pipes A and B operating simultaneously can empty the tank in half the time that of C, third pipe, alone takes to empty it. Pipe A working alone takes half the time taken by pipe B. Together they take to fill the tank in 6 hrs 40 mins. What is time taken for A to empty the tank alone ? |
1) | 11hrs | 2) | 12 hrs |
3) | 11-1/9hrs | 4) | 12-1/3hrs |
5) | None of these |
Answer : 11-1/9hrs
Explanation :
Explanation :
Let, C pipe takes x hrs ,then A pipe takes x/2 hrs
So, C pipe takes
=2(x+x/2) =3x hrs
Then, (A+B+C) pipes can
do in 1 hr = 1/x + 2/x +1/3x = 10/3x hrs
But given , total
time taken by all pipes = 6 hrs 40 min =
6-2/3 hrs = 20/3 hrs
So, 10/3x hrs = 3/20
Or x =200/9 hrs i.e time
taken for pipe B
Therefore, time taken
for pipe A = (200/9)/2 = 100/9 = 11-1/9hrs

Q3. |
|
1) | 8hrs | 2) | 10hrs |
3) | 12hrs | 4) | 14hrs |
5) | None of these |
Answer : 14hrs
Explanation :
Explanation :


Q4. |
|
1) | 2 hour | 2) | 3 hour |
3) | 4 hour | 4) | 6 hour |
5) | None of these |
Answer : 6 hour
Explanation :

Explanation :


Q5. |
|
1) | 80 gallons | 2) | 120 gallons |
3) | 140 gallons | 4) | 160 gallons |
5) | None of these |
Answer : 120 gallons
Explanation :

Explanation :


Q6. |
|
1) | 81 min. | 2) | 108 min. |
3) | 144 min. | 4) | 164 min. |
5) | None of thesae |
Answer : 144 min.
Explanation : Let, the slower pipe alone will fill the tank in x minutes.
Explanation : Let, the slower pipe alone will fill the tank in x minutes.


Q7. |
|
1) | 15 min., 20 min | 2) | 15 min, 10 min |
3) | 10 min, 15 min | 4) | 25 min, 20 min |
5) | None of these |
Answer : 10 min, 15 min
Explanation :

Explanation :


Q8. |
|
1) | 7.5 hours | 2) | 8 hours |
3) | 8.5 hours | 4) | 12 hours |
5) | None of these |
Answer : 7.5 hours
Explanation : Work done by all the tanks working together in 1 hour.
Explanation : Work done by all the tanks working together in 1 hour.


Q9. |
|
1) | 12 hour | 2) | 15 hour |
3) | 24 hour | 4) | 30 hour |
5) | None of these |
Answer : 30 hour
Explanation :
Explanation :
Let, the leak empties the tank in x hours.


Q10. | A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. What is time for the first pipe to fill up the tank alone ? |
1) | 10hrs | 2) | 12hrs |
3) | 15hrs | 4) | 18hrs |
5) | None of these |
Answer : 15hrs
Explanation :
Explanation :
Let, the first pipe can alone takes x hours to fill the tank .
Then, second and third pipes will take (x -5) and (x - 9) hours respectively .
Then, second and third pipes will take (x -5) and (x - 9) hours respectively .
So,(1/x) + (1/x-5) = 1/x-9.
Solving,we get x =15
