Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q1. | Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and given answers if . 1) x > y 2) x y 3) x < y 4) x y 5) x = y or the relationship cannot be established
20x^{2} – x – 12 = 0 20y^{2} + 27y + 9 = 0 |
Answer : 2
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Q2. | Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and given answers if . 1) x > y 2) x y 3) x < y 4) x y 5) x = y or the relationship cannot be established
I. x^{2} + 8x + 15 = 0 II. y^{2} + 13y + 42 = 0 |
Answer : 1
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Q3. | Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and given answers if . 1) x > y 2) x y 3) x < y 4) x y 5) x = y or the relationship cannot be established
I. x^{2} - 4x + 3 = 0 II. y^{2} - 7y + 12 = 0 |
Answer : 1
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Q4. | Find the range of values of x for which x^{2} + 6x -27 > 0 |
1) | x < -9 or x < 3 |
2) | x < -9 or x > 3 |
3) | x > -9 or x > 3 |
4) | x > -9 or x < 3 |
5) | None of these |
Answer : x > -9 or x > 3
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Q5. | Find the range of values of x for which x^{2} + 6x -27 > 0 |
1) | x < -9 or x < 3 |
2) | x < -9 or x > 3 |
3) | x > -9 or x > 3 |
4) | x > -9 or x < 3 |
5) | None of these |
Answer : x > -9 or x > 3
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Q6. | Prove that, 8x - 15 - x^{2} > 0 for limited value of of x and also find the limits. |
1) | 3 > x < 5 |
2) | 3 < x > 5 |
3) | 3 < x < 5 |
4) | 3 > x > 5 |
5) | None of these |
Answer : 3 < x < 5
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Q7. | What shoul be real values of x, in the given expression x^{2} - 2x - 3 > 0 |
1) | x > -1 or x > 3 |
2) | x < -1 or x > 3 |
3) | x > -1 or x < 3 |
4) | x > -1 or x < 3 |
5) | None of these |
Answer : x < -1 or x > 3
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Q8. | Which of the following values of x will satisfy the inequality x^{2} - 5x + 6 < 0 |
1) | 2< x < 3 |
2) | -2 < x < 2 |
3) | -3 < x < -2 |
4) | -3 < x < 2 |
5) | None of these |
Answer : 2< x < 3
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Q9. | Which of the following values of x will satisfy the inequality x^{2} -x - 6 > 0 ? |
1) | x < -2 or x > 3 |
2) | -2 < x < 3 |
3) | -3 < x < 2 |
4) | x> -2 or x < 3 |
5) | None of these |
Answer : x < -2 or x > 3
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Q10. | Directions : In each of the following questions two questions two equations I and II are given. You have to solve both the equation and give answer. 1) if a <b 2) If a is less than or equal b 3) if a is greater than or equal to b 4) if a = b 5) if a > b
I. 6a^{2 }+ 5a + 1 = 0 II. 5b^{2 }+ 19b + 6 = 0 |
1) | 1 |
2) | 2 |
3) | 3 |
4) | 4 |
5) | None of these |
Answer : None of these
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