Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q1. | In a triangle ABC, the sides AB and AC have been produced to D and E. Bisectors of angle CBD and angle BCE meet at O. If angle A = 64°, then angle BOC is - |
1) | 54° | 2) | 56° |
3) | 58° | 4) | 60° |
5) | None of these |
Answer : 58°

Q2. |
|
1) | 2 | 2) | 3 |
3) | 4 | 4) | 5 |
5) | None of these |
Answer : 5
Explanation :
Explanation :
Since, DE parallel to BC ![]()
![]()
![]()


so, (AD / DB) = (AE / EC)
or {x / (x – 2)} = {(x + 2) / (x – 1)}
or x(x – 1) = (x + 2) (x – 1)
or x2 – x = x2 – 4
or x = 4 .
