Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q191. |
|
| 1) | (2^16 + 1) | 2) | (2^16 - 1) |
| 3) | (7 x 2^23) | 4) | (2^96 + 1) |
| 5) | None of these | ||
Answer : (2^96 + 1)
Explanation :
Explanation :
Let, 232 = x. Then, (232 + 1) = (x + 1).
Let, (x + 1) be completely divisible by the natural number N.
Then, (296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.
π Click "View Answer" to reveal correct option
View Answer
Q192. |
|
| 1) | 475 | 2) | 525 |
| 3) | 545 | 4) | 550 |
| 5) | None of these | ||
Answer : 525
Explanation : Let, the Full Mark be 100%.
Explanation : Let, the Full Mark be 100%.
A boy scored 483 marks and failed by 117 marks i.e. the pass mark be 483 + 117 = 600
So, 40% = 600
or 100% = (600/40) x 100 = 1500
The minimum passing marks for the girls is = 1500 x (35/100) = 525
π Click "View Answer" to reveal correct option
View Answer
Q193. |
Directions : Study the information carefully to answer the questions that follow. On the occasion of a opening ceremony of a sports event, in a stadium there are 600 palyers in all who are participating in four different events, viz, Athletics, Table Tennis, KhoKho and Lawn Tennis. The ratio of male to female players is 11 : 4. 30% of the female players are participating in Athletics. 10% of the female players are participating in Table Tennis. The remaining female players are participating in KhoKho and Lawn Tennis in the ratio of 1 : 3. The ratio of male players who are participating in Athletics and other events together is 3 : 5. 4% of those male players who are not participating in Athletics are participating in Lawn Tennis. Remaining male players are participating in Table Tennis and KhoKho in the ratio of 5:3. What is the total number of female players who are participating in Athletics and KhoKho together ? |
| 1) | 64 | 2) | 68 |
| 3) | 72 | 4) | 84 |
| 5) | None of these | ||
Answer : 72
π Click "View Answer" to reveal correct option
View Answer
Q194. |
|
| 1) | 23 | 2) | 27 |
| 3) | 33 | 4) | 38 |
| 5) | None of these | ||
Answer : 27
π Click "View Answer" to reveal correct option
View Answer
Q195. |
|
| 1) | 7 : 2 | 2) | 9 : 2 |
| 3) | 11 : 3 | 4) | 13 : 4 |
| 5) | None of these | ||
Answer : 9 : 2
π Click "View Answer" to reveal correct option
View Answer
Q196. |
|
| 1) | 9 : 16 | 2) | 11 : 14 |
| 3) | 11 : 16 | 4) | D.I |
| 5) | None of these | ||
Answer : 11 : 16
Explanation : Answer : 11 : 16
Explanation : Answer : 11 : 16
π Click "View Answer" to reveal correct option
View Answer
Q197. |
|
| 1) | 15 m | 2) | 17.5 m |
| 3) | 24 m | 4) | 20 m |
| 5) | None of these | ||
Answer : 20 m
Explanation :
Explanation :
The area of a square is 225 m2.
Sides of the square is = 15 m.
So, perimeter = 15 X 4 = 60 mts.
Given that perimeter of the equilateral triangle is also equal
3x = 60
or x = 60/3 = 20 mtrs
π Click "View Answer" to reveal correct option
View Answer
Q198. |
|
| 1) | x/2 | 2) | x |
| 3) | 2x | 4) | 3x |
| 5) | None of these | ||
Answer : 2x
Explanation :
Explanation :
Area of a square is x2.
Area of the triangle is ½ x.
Let, the altitude be h.
x2 = ½ xh ½ h = x h = 2x.
π Click "View Answer" to reveal correct option
View Answer
Q199. |
|
| 1) | Rs.1650 | 2) | Rs.2000 |
| 3) | Rs.2400 | 4) | Rs.3500 |
| 5) | None of these | ||
Answer : Rs.1650
Explanation :
Explanation :
Short-cut Method :
(Final Strength X Increases Value) + earlier average
i.e. ( 17 X 50) + 800 = Rs. 1650
π Click "View Answer" to reveal correct option
View Answer
Q200. |
|
| 1) | 17 years | 2) | 18 years |
| 3) | 19 years | 4) | 20 years |
| 5) | None of these | ||
Answer : 19 years
Explanation : The total age of 50 students = 50 X 16 = 800 yrs.
Explanation : The total age of 50 students = 50 X 16 = 800 yrs.
After admitted 10 new students ,total age become 60 X 16.5 = 990 yrs.
So, age of new students = 990 -800 = 190 yrs.
Thus, their average 190 /10 = 19 yrs.
π Click "View Answer" to reveal correct option
View Answer