Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q251. |
|
| 1) | Rs.17,000 | 2) | Rs.20,000 |
| 3) | Rs.25,500 | 4) | Rs.38,000 |
| 5) | None of these | ||
Answer : Rs.38,000
Explanation :

Explanation :

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Q252. |
|
| 1) | 20 litres | 2) | 30 litres |
| 3) | 40 litres | 4) | 60 litres |
| 5) | None of these | ||
Answer : 60 litres
Explanation :

Explanation :

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Q253. |
|
| 1) | 2 : 5 | 2) | 3 : 5 |
| 3) | 4 : 5 | 4) | 6 : 7 |
| 5) | None of these | ||
Answer : 4 : 5
Explanation :

Explanation :

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Q254. |
|
| 1) | 24 | 2) | 38 |
| 3) | 42 | 4) | 48 |
| 5) | Non of these | ||
Answer : 38
Explanation :
Explanation :
Let, the numbers be x and x + 2.
Then, (x + 2)2 - x2 = 84
or 4x + 4 = 84 or 4x = 80
or x = 20. The required sum = x + (x + 2) = 2x + 2 = 42.
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Q255. |
|
| 1) | 235 | 2) | 253 |
| 3) | 273 | 4) | 352 |
| 5) | None of these | ||
Answer : 253
Explanation :
Explanation :
Let, the middle digit be x.
Then, 2x = 10 or x = 5. So, the number is either 253 or 352.
Since the number increases on reversing the digits, so the hundred's digits is smaller than the unit's digit.
Hence, required number = 253.
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Q256. |
|
| 1) | 18 | 2) | 24 |
| 3) | 42 | 4) | 81 |
| 5) | None of these | ||
Answer : 24
Explanation :
Explanation :
Let, the ten's and unit digit be x and y respectively.
So, xy = 8 and the number be 10x+y
When 18 is added, the number be 10x+ y +18.
Then, 10x + y + 18 = 10 y + x
or 9x - 9y = -18 x - y = - 2
We know that (x+y)2=( x-y)2 + 4xy = (-2)2 + 4 x 8 =36
or x+y = 6
By solving we get x = 2 and y = 4
Thus, the number is 24.
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Q257. |
|
| 1) | 3 | 2) | 5 |
| 3) | 10 | 4) | 11 |
| 5) | None of these | ||
Answer : 11
Explanation :
Explanation :
Let, the ten's digit be x and unit's digit be y.
Then, number = 10x + y.
Number obtained by interchanging the digits = 10y + x.
(10x + y) + (10y + x) = 11(x + y), which is divisible by 11
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Q258. |
|
| 1) | 4 | 2) | 8 |
| 3) | 12 | 4) | 14 |
| 5) | None of these | ||
Answer : 8
Explanation :
Explanation :
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let, ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36
or 9x = 36
or x = 4.
So, required difference = (2x + x) - (2x - x) = 2x = 8.
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Q259. |
|
| 1) | 1 | 2) | 53 |
| 3) | 66 | 4) | 67 |
| 5) | None of these | ||
Answer : 66
Explanation :
Explanation :
(xn + 1) will be divisible by (x + 1) only when n is odd.
(6767 + 1) will be divisible by (67 + 1)
(6767 + 1) + 66, when divided by 68 will give 66 as remainder.
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Q260. |
|
| 1) | 19 | 2) | 21 |
| 3) | 23 | 4) | 45 |
| 5) | None of these | ||
Answer : 23
Explanation :
Explanation :
Let, the numbers be x and y.
Then, xy = 120 and x2 + y2 = 289.
(x + y)2 = x2 + y2 + 2xy = 289 + (2 x 120) = 529
x + y = 529 = 23.
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