Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q21. | How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is not allowed ? |
| 1) | 30 | 2) | 48 |
| 3) | 60 | 4) | 120 |
| 5) | None of these | ||
Answer : 60
Explanation :
Explanation :
Let the 3-digit number be ABC, where C is at the units place, B at the tens place and A at the hundreds place.
Now when repetition is not allowed,
The number of digits possible at C is 5. Let’s suppose one of 5 digits occupies place C, now as the repletion is not allowed, the possible digits for place B are 4 and similarly there are only 3 possible digits for place A.
Therefore, The total number of possible 3-digit numbers = 5 × 4 × 3=60
View AnswerQ22. | How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is allowed ? |
| 1) | 60 | 2) | 90 |
| 3) | 120 | 4) | 240 |
| 5) | None of these | ||
Answer : 120
Explanation : Let the 3-digit number be ABC, where C is at the units place, B at the tens place and A at the hundreds place.
Now when repetition is allowed,
The number of digits possible at C is 5. As repetition is allowed, the number of digits possible at B and A is also 5 at each.
Hence, the total number possible 3-digit numbers =5 × 5 × 5 =125
Explanation : Let the 3-digit number be ABC, where C is at the units place, B at the tens place and A at the hundreds place.
Now when repetition is allowed,
The number of digits possible at C is 5. As repetition is allowed, the number of digits possible at B and A is also 5 at each.
Hence, the total number possible 3-digit numbers =5 × 5 × 5 =125
View AnswerQ23. | Two patterners A and B invested Rs. 1250/ and Rs.850 in a in a business respectively. Both the patterners distributes 37% of the profits equally and rest of the profit according to their ratio of capital investments. If one partners gets Rs.30 more than other, then what should be the total profit in the business. |
| 1) | Rs.225 | 2) | Rs.250 |
| 3) | Rs.275 | 4) | Rs.280 |
| 5) | None of these | ||
Answer : Rs.250
Explanation : The ratio of capital of A and B =1250:850 = 25:17
Explanation : The ratio of capital of A and B =1250:850 = 25:17
A and B equally share the total of 37%.
Now, rest 63% is divided in the ratio 25:17.
So, A.T.Q (63/42) x 25 - (63/42)x 17 = Rs.30
Or (63/42) x (25-17) = (63/42) x 8 = 30
Or (1.5 x 8 ) % = 30
So, total profit =i.e. 100% =12 x 30 =Rs.250
View AnswerQ24. | The LCM and HCF of two numbers are 660 and 10 respectively. If the sum of the numbers is 170, the what should be difference of the numbers ? |
| 1) | 30 | 2) | 40 |
| 3) | 48 | 4) | 50 |
| 5) | None of these | ||
Answer : 50
Explanation : Let , two numbers are 10a and 10b ,where a and b are relatively prime numbers.
Explanation : Let , two numbers are 10a and 10b ,where a and b are relatively prime numbers.
According to the question,10a X b = 660
or ab = 66 ------------- (i)
Also given, 10a + 10b = 170
or a + b = 17 ------------------- (ii)
Solving Eqs. (i) and (ii) we get a = 11 and b = 6
So, numbers are 110 and 60.
Thus, the difference is 110 - 60 = 50
View AnswerQ25. | Thrice the age of A is 7 times B's age. And C’s age is half of A's age. Also, nine years ago, A's age was one-third of B’s age then. What is the ratio between the age of the A,B and C age respectively ? |
| 1) | 11:6:7 | 2) | 11:6:3 |
| 3) | 14:6:3 | 4) | 14:6:7 |
| 5) | None of these | ||
Answer : 14:6:7
Explanation : Given, 3A = 7B
Explanation : Given, 3A = 7B
or 3A - 7B = 0 ---------(I) and A = 2C --------- (II)
And A-9 = (B-9)/3
or 3A-27 = B-9
or 3A - B = 18 ---------- (III)
from equations I and III , we get B = 3
A= 7 and C = 3.5
So, ratio of A,B and C i.e. A:B:C= 14:6:7
View AnswerQ26. |
|
| 1) | Rs.10,480 | 2) | Rs.11,240 |
| 3) | Rs.11,520 | 4) | Rs.12,420 |
| 5) | None of these | ||
Answer : Rs.11,520
Explanation :
Explanation :
Let the width of the rectangle = x m
Then, 250% of x = 40
x = 40 × 100/250 = 16 m
Perimeter of the rectangle = 2(length + width) = 2 × (40 + 16) = 112 cm
Perimeter of the square = (112 + 16) = 128 m
The sides of the square = 128/4 = 32 m
The area of the square field without street = (32)2 sq. cm = 1024 sq. m
The area of the square field with street = (32 + 8)2 sq. cm = 1600 sq. m
The area of the street = 1600 - 1024 = 576 sq. m
The total cost of constructing the street = 576 × 20 = Rs.11,520
View AnswerQ27. | A person invested a total amount of Rs 15 lakh. A part of it was invested in a fixed deposit earning 6% annual interest, and the remaining amount was invested in two other deposits in the ratio 2 : 1, earning annual interest at the rates of 4% and 3%, respectively. If the total annual interest income is Rs 76000 then what was the amount (in Rs lakh) invested in the fixed deposit ? |
| 1) | Rs. 6 Lakhs | 2) | Rs. 7 Lakhs |
| 3) | Rs. 8 Lakhs | 4) | Rs. 9 Lakhs |
| 5) | None of these | ||
Answer : Rs. 9 Lakhs
Explanation :
Explanation :
Let Rs x be invested in FD.
So, Remaining amount = Rs. 15 Lakhs - x, which is invested in the ratio 2 : 1
So, each investment would have 1/3(15-x) and 2/3(15-x) investments respectively
So, Total annual interest income = 6% of x + 4% of 1/3(15-x) + 3% of 2/3(15-x) = 76000
Rewriting Rs.76000 as Rs. 0.76 Lakhs,
6% of x + 4% of 1/3(15-x) + 3% of 2/3(15-x) = 0.76
Multiply both sides by 100,
6x + 4/3(15-x) + 2(15-x) = 76
6x +11/3 (15-x) = 76
165 + 18x -11x = 228
7x = 63
x = 9 (or) Rs. 9 Lakhs
View AnswerQ28. |
|
| 1) | 60 | 2) | 70 |
| 3) | 72 | 4) | 80 |
| 5) | None of these | ||
Answer : 80
Explanation :
Explanation :
Let, the total Maximum marks in exam = 100%
His score = 50% of 100 = 50
His marks after review = 140% of 50 = 70
His marks after post review = 120% of 70 = 84
A.T.Q 84% – 12 =70% + 30
14% = 42
or 100% = 300
So passing marks = 300(70/100) + 30 = 240
Total marks = 100% = 300
Thus, required percentage score needed for passing the examination = (240/300 ) X 100 = 80%
View AnswerQ29. |
|
| 1) | 5-3/10 days | 2) | 6-7/10 days |
| 3) | 6-3/10 days | 4) | 7-3/10 days |
| 5) | None of these | ||
Answer : 6-3/10 days
Explanation : A,B and C altogether work for 3 days = 3 (1/12+1/18+1/24) = 13/24 parts
Explanation : A,B and C altogether work for 3 days = 3 (1/12+1/18+1/24) = 13/24 parts
So, remaining (1-13/24) = 11/24 parts
B and C can do in 1 day (1/12+1/18) = 5/36 parts
Now, B & C can do this in (11/24 )/(5/36) = 33/10 days = 3-3/10 days
So, overall time taken to complete this workpiece = 6-3/10 days
View AnswerQ30. |
|
| 1) | 2 | 2) | 4 |
| 3) | 5 | 4) | 6 |
Answer : 8
Explanation :
Explanation :
Bag X:
Two balls taken from bag x, total probability,
According to the question,
40/87 = (Probability of getting 1st green and second blue * Probability of getting 1st blue and second green)
Take green = 10 and blue = 20
According to the question,
40/87 = 10 * 20 * 2/(30 * 29)
40/87 = 40/87
Let us take number of green balls taken out from bag Y be a
Number of blue balls taken out from bag Y = a + 4
According to the question,
(10 + a)C2/(30 + 2a + 4)C2 = 13/123
(10 + a) * (9 + a)/[(34 + 2a) * (33 + 2a)] = 13/123
Simplify the equation we get, a = 4
Number of blue balls taken out from bag Y = a + 4 = 4 + 4 = 8
View Answer