Reasoning
ISBT Reasoning for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q61. |
|
1) | 27 | 2) | 64 |
3) | 125 | 4) | 216 |
5) | None of these |
Answer : 125
Explanation : The number of cubes where no face is painted = The number of cubes who one face is visible
Explanation : The number of cubes where no face is painted = The number of cubes who one face is visible
= (a - 2)3 = (7 - 2)3 = 125.

Q62. | Direction : A cube is painted red and all its faces and is then divided into 343 equal cubes.How many cubes will have one face painted ? |
1) | 112 | 2) | 148 |
3) | 150 | 4) | 162 |
5) | None of these |
Answer : 150
Explanation : The number of cubes whose one face is painted = The number of cubes who one face is visible = 6 (a - 2)2 = 6 (7 - 2)2 = 150
Explanation : The number of cubes whose one face is painted = The number of cubes who one face is visible = 6 (a - 2)2 = 6 (7 - 2)2 = 150

Q63. |
|
1) | 45 | 2) | 50 |
3) | 56 | 4) | 60 |
5) | None of these |
Answer : 60
Explanation :
Explanation :
Since, the cube is divided into 343 equal cubes i.e. (7)3 equal cubes, assume the edge length of the cube to be 7, (a = 7). This is done using the idea of unit cubes. (A cube of edge length a unit can be divided into a3 unit cubes)
The number of cubes whose two faces are painted = The number of cubes whose two faces are visible = 12 (a - 2) = 12 (7 - 2) = 60

Q64. |
|
1) | 0 | 2) | 4 |
3) | 8 | 4) | 16 |
5) | None of these |
Answer : 8
Explanation :
Explanation :
Since the cube is divided into 343 equal cubes i.e. (7)3 equal cubes, assume the edge length of the cube to be 7, (a = 7). This is done using the idea of unit cubes. (A cube of edge length a unit can be divided into a3 unit cubes)
The number of cubes whose three face are painted is equal to the number of cubes whose three faces are visible. (Since only those faces which are visible can be painted).
Hence, the number is 8.

Q65. |
|
1) | T | 2) | R |
3) | U | 4) | D.I |
5) | None of these |
Answer : R
Explanation :
Explanation :
Books Persons
R C
T B/ E
Q A
P F
S B/E
U D

Q66. |
|
1) | B | 2) | E |
3) | D | 4) | C |
5) | None of these |
Answer : D
Explanation :
Explanation :
Books Persons
R C
T B/ E
Q A
P F
S B/E
U D

Q67. |
|
1) | Q | 2) | S |
3) | P | 4) | T |
5) | None of these |
Answer : Q
Explanation :
Explanation :
Books Persons
R C
T B/ E
Q A
P F
S B/E
U D

Q68. |
|
1) | Between B and C | 2) | Between D and C |
3) | Between E and D | 4) | Between C and E |
5) | None of these |
Answer : Between B and C
Explanation : The sequence is : E B A C D
Explanation : The sequence is : E B A C D
So, A is sitting between B and C.

Q69. |
|
1) | A | 2) | B |
3) | C | 4) | D |
5) | None of these |
Answer : A
Explanation : The above arrengement is : G B C D E F A
Explanation : The above arrengement is : G B C D E F A
So, 'D' is sitting in the center.

Q70. |
|
1) | 8 | 2) | 10 |
3) | 12 | 4) | 16 |
5) | None of these |
Answer : 12
Explanation : The sequence is : (3+6) +3=12, (5+10) +5 =20
Explanation : The sequence is : (3+6) +3=12, (5+10) +5 =20
So, (4 +8) = 12
