Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q41.  What should be the remainder when 2 ^{100} is divided by 101 ? 
1)  1  2)  11 
3)  99  4)  100 
5)  None of these 
Answer : 99
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Q42. 

1)  425  2)  480 
3)  520  4)  625 
5)  None of these 
Answer : None of these
Explanation : Let, the full mark be 100%.
Explanation : Let, the full mark be 100%.
A boy should requires marks to pass = 483 +117 = 600
So, the full mark = 600 i.e. 100%
So, the required mark for a girl should = (600/40) x 35 = 525
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Q43. 

1)  118 : 163  2)  128 : 119 
3)  121 : 147  4)  163 : 118 
5)  None of these 
Answer : None of these
Explanation :
Explanation :
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Q44. 

1)  Rs. 98.5 lakhs  2)  Rs. 89.3 lakhs 
3)  Rs. 92.6 lakhs  4)  Can’t be determined 
5)  None of these 
Answer : Can’t be determined
Explanation :
Explanation :
As the percentage profits are different for different years, we can not find the total income
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Q45. 

1)  Rs. 74.8 Lakhs  2)  Rs. 85.5 Lakhs 
3)  Rs. 68.4 Lakhs  4)  Rs. 78.5 Lakhs 
5)  None of these 
Answer : Rs. 85.5 Lakhs
Explanation :
Explanation :
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Q46. 

1)  4 : 15  2)  7 : 12 
3)  9: 16  4)  Cannot determined 
5)  None of these 
Answer : 9: 16
Explanation :
Explanation :
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Q47. 

1)  Rs.32 lakhs  2)  Rs.46 lakhs 
3)  Rs.16 lakhs  4)  Cannot determined 
5)  None of these 
Answer : Rs.32 lakhs
Explanation :
Explanation :
Total expenditure of A and B in 2011 = 2 x 16 = 32 lakhs
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Q48.  Seven men and four boys can complete a work in 6 days. A man completes the double work than a boy. In how many days will 5 men and 4 boys complete the work ? 
1)  4  2)  5 
3)  6  4)  8 
5)  None of these 
Answer : None of these
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Q49.  Directions : Study the graphs carefully to answer the questions that follow: Total number of children in six different schools and the percentage of girls are give bellow in the linechart. The numbers of boys in school Q is how much percentage (approx.) more or less than the numbers of girls in the school S ? 
1)  140  2)  142 
3)  144  4)  148 
5)  None of these 
Answer : 142
Explanation : The numbers of boys in school Q = (3000 x 55/100) = 1650
Explanation : The numbers of boys in school Q = (3000 x 55/100) = 1650
The numbers of girls in the school S = (2250 x 30/100) = 675
So, different = 1650  675 = 975
Therefore , required more % = (975/675) x 100 = 144 % (approx.)
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Q50.  Directions : Study the graphs carefully to answer the questions that follow: Total number of children in six different schools and the percentage of girls are give bellow in the linechart. What is number of boys in school P and Q are more than girls in school of S and T ? 
1)  1475 more  2)  1655 less 
3)  1875 more  4)  1975 more 
5)  None of these 
Answer : 1975 more
Explanation : Total number of boys in school P and Q = [ (2500 x 60/100) + (3000 x 55/100) ] =1500 + 1650 = 3150.
Explanation : Total number of boys in school P and Q = [ (2500 x 60/100) + (3000 x 55/100) ] =1500 + 1650 = 3150.
Total number of girls in school S and T = [ (2250 x 30/100) + (1250 x 40/100) ] = 675 + 500 = 1175
So, the different = 3150 1175 = 1975
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