Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q1. 

1)  Rs.10,480  2)  Rs.11,240 
3)  Rs.11,520  4)  Rs.12,420 
5)  None of these 
Answer : Rs.11,520
Explanation :
Explanation :
Let the width of the rectangle = x m
Then, 250% of x = 40
x = 40 × 100/250 = 16 m
Perimeter of the rectangle = 2(length + width) = 2 × (40 + 16) = 112 cm
Perimeter of the square = (112 + 16) = 128 m
The sides of the square = 128/4 = 32 m
The area of the square field without street = (32)^{2} sq. cm = 1024 sq. m
The area of the square field with street = (32 + 8)^{2} sq. cm = 1600 sq. m
The area of the street = 1600  1024 = 576 sq. m
The total cost of constructing the street = 576 × 20 = Rs.11,520
View Answer
Q2.  The length of a rectangle increases by 20% and also its breadth increases by 15% . What should be the percentage change in its perimeter? 
1)  35%  2)  36% 
3)  38%  4)  Can't be determined 
5)  None of these 
Answer : Can't be determined
View Answer
Q3. 

1)  100.8 sq cm  2)  112.4 sq cm 
3)  104.2 sq cm  4)  Cannot be determined 
5)  None of these 
Answer : 100.8 sq cm
View Answer
Q4.  The ratio of the adjacent angles of a parallelogram is 7 : 8. Also, the ratio of the angles of quadrilateral is 5 : 6 : 7 : 12. What is the sum of the smaller angle of the parallelogram and the second largest angle of the quadrilateral ? 
1)  136°  2)  156° 
3)  168°  4)  208° 
5)  None of these 
Answer : 168°
Explanation :
Explanation :
Sum of the adjacent angles of a parallelogram is 180°.
Smaller angle of the parallelogram = 7/15 × 180 = 84°
Second largest angle of the quadrilateral = 7/30 × 360 = 84°
Required sum = 84 + 84 = 168°
View Answer
Q5.  The smallest side of a rightangled triangle is 8 cm less than the side of a square of perimeter 56 cm. The second largest side of the rightangled triangle is 4 cm less than the length of the rectangle of area 96 sq cm and breadth 8 cm. What is the largest side of the rightangled triangle ? 
1)  10 cm  2)  12 cm 
3)  15 cm  4)  18 cm 
5)  None of these 
Answer : 10 cm
Explanation :
Explanation :
Side of the square = 56/4 = 14 cm
smallest side of the triangle = 14 – 8 = 6 cm
Length of the rectangle = 96/ 8 = 12 cm
Second largest side of the triangle = 112 – 4 = 8 cm
So, Largest side of the triangle = square root of 6^{2} + 8^{2 } = 10 cm
View Answer
Q6. 

1)  1/3  2)  1/4 
3)  1/2  4)  No change 
5)  None of these 
Answer : 1/2
Explanation :
Explanation :
Let the length and breadth of the rectangle be L and B respectively.
Area = L x B = LB
View Answer
Q7. 

1)  25  2)  36 
3)  38  4)  30 
5)  None of these 
Answer : 36
Explanation :
Explanation :
The smallest angle = 3/15 x 180° = 36°
The largest angle =7/15 x 180° = 84°
So, (36 x 2)  (84/ 2) = 36
View Answer
Q8. 

1)  344.35 cm2  2)  462 cm2 
3)  498.35 cm2  4)  456cm2 
5)  None of these 
Answer : 498.35 cm2
Explanation :
Explanation :
View Answer
Q9. 

1)  18.8 cm  2)  23.5 cm 
3)  24 cm  4)  31.3cm 
5)  None of these 
Answer : 24 cm
Explanation :
Explanation :
The final ratio of the triangle are 20 : 15 : 12
Perimeter = 20x + 15x + 12x = 47 x
So, 47x = 94
or = x = 2
Thus smallest side = 122 = 24 cm.
View Answer
Q10. 

1)  16 cm  2)  18 cm 
3)  24 cm  4)  Data Inadequate 
5)  None of these 
Answer : 18 cm
Explanation :
Explanation :
2(l + b) /b = 5/1 or 2l + 2b = 5b
or 3b = 2l b =2l/3
Then, Area = 216 cm2
l x b = 216
l x2l/3 = 216 or l^{2 }= 324
or l = 18 cm.
View Answer