Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q1.  The sum of two numbers is 27 and their H.C.F is 3. If one of the number is lies between 13 to 16, the find the value of the other number ? 
1)  12  2)  15 
3)  18  4)  24 
5)  None of these 
Answer : 12
Explanation : Let, two numbers are 3x and 3y respectively.
Explanation : Let, two numbers are 3x and 3y respectively.
Then, 3x + 3y = 27
or 3 (x + y) = 27
or (x + y) = 27/3 = 9
So, pairs of numbers are 9 = (1,8) , (2,7) , ( 3,6) and (4,5) .
Thus the numbers are 3 x 4 = 12 and 3 x 5 =15
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Q2.  What is fourdigit largest number which when divided by 4, 5 , 6, 8 and 12 leaves reminder is zero in each case ? 
1)  9936  2)  9950 
3)  9960  4)  9990 
5)  None of these 
Answer : 9960
Explanation : The L.C.M of 4, 5 , 6, 8 and 12 is 120.
Explanation : The L.C.M of 4, 5 , 6, 8 and 12 is 120.
The fourdigit largest number is 9999.
Then, if 9999 is divided by 120, reminder is 39.
So, the require number = 9999  39 = 9960.
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Q3.  A rectangular size floor has 240 feet length and 200 feet wide. How many largest square size marbels slabs are require to pave ,so that no waste of slabs in the paving ? 
1)  24  2)  25 
3)  30  4)  36 
5)  None of these 
Answer : 30
Explanation : The H.C.F of 240 and 200 is 40.
Explanation : The H.C.F of 240 and 200 is 40.
Area of the floor = (240 X 200) square feet and area of the slab is (40X40) square feet.
So, Numbers of slabs require = (240 X 200)/(40X40) = 30.
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Q4.  A worker has paid Rs.4320 if he works for all day but he has paid Rs.2520 due to some days of absent in a month.How many days he was absent ? 
1)  2 days  2)  3 days 
3)  4 days  4)  5 days 
5)  None of these 
Answer : 5 days
Explanation : The H.C.F of 4320 and 2520 is 360.
Explanation : The H.C.F of 4320 and 2520 is 360.
So, 4320/360 = 12 days and 2520/360 = 7 days
Thus, numbers of he absent =127=5 days.
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Q5. 

1)  78  2)  91 
3)  104  4)  117 
5)  None of these 
Answer : 91
Explanation : Let, two numbers are 13x and 13y respectively.
Explanation : Let, two numbers are 13x and 13y respectively.
So, 13x X 13y = 13 X 455
or xy = 35
Then, pairs of numbers are 35 = (1 X 35) , (5 x 7).
So, second pairs is considerable i.e. 13X5 = 65 and 13 X 7 = 91
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Q6. 

1)  10  2)  12 
3)  15  4)  20 
5)  None of these 
Answer : 10
Explanation : Let, two numbers are 5x and 5y respectively.
Explanation : Let, two numbers are 5x and 5y respectively.
So, 5x X 5y = 5 X 495
or 25xy = 5 X 495
or xy = 99
So, pairs of numbers are i.e. 99 = (1 X 99) and (9 x 11)
Therefore , the satisfy numbers are 9 x 5 = 45 and 11 x 5 = 55
So, the difference is 55  45 = 10.
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Q7. 

1)  215  2)  220 
3)  225  4)  235 
5)  None of these 
Answer : 225
Explanation : Given that, 45 H.C.F = L.C.M and
Explanation : Given that, 45 H.C.F = L.C.M and
H.C.F + L.C.M = 1150
or H.C.F + 45 H.C.F = 1150
or 46 H.C.F = 1150
or H.C.F = 1150/46 =25
So, L.C.M = 25 X 45 = 1125
Now, we can get 125 X x = 25 X 1125
or x = (25 X 1125) /125 = 225
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Q8. 

1)  196  2)  630 
3)  1260  4)  2520 
5)  None of these 
Answer : 630
Explanation :
Explanation :
L.C.M. of 12, 18, 21 30
= 1260.
So, required number = (1260 รท 2) = 630.
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Q9. 

1)  1677  2)  1683 
3)  2523  4)  3363 
5)  None of these 
Answer : 1683
Explanation :
Explanation :
L.C.M. of 5, 6, 7, 8 = 840.
Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2.
Required number = (840 x 2 + 3) = 1683.
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Q10. 

1)  55/601  2)  12/55 
3)  11/120  4)  11/112 
5)  None of these 
Answer : 11/120
Explanation :
Explanation :
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