ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
A tank has three drain pipes, the first two pipes A and B operating simultaneously can empty the tank in half the time that of C, third pipe, alone takes to empty it. Pipe A working alone takes half the time taken by pipe B. Together they take to fill the tank in 6 hrs 40 mins. What is time taken for A to empty the tank alone ?
||2)|| 12 hrs
|5)||None of these |Answer : 11-1/9hrs
Let, C pipe takes x hrs ,then A pipe takes x/2 hrs
So, C pipe takes
=2(x+x/2) =3x hrs
Then, (A+B+C) pipes can
do in 1 hr = 1/x + 2/x +1/3x = 10/3x hrs
But given , total
time taken by all pipes = 6 hrs 40 min =
6-2/3 hrs = 20/3 hrs
So, 10/3x hrs = 3/20
Or x =200/9 hrs i.e time
taken for pipe B
Therefore, time taken
for pipe A = (200/9)/2 = 100/9 = 11-1/9hrs
Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. In how many hours the pipe C alone can fill the tank ?
|5)||None of these|Answer : 14hrs
Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately ?
|1)|| 2 hour
||2)|| 3 hour
|3)|| 4 hour
||4)|| 6 hour
|5)||None of these|Answer : 6 hour
Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. What is the capacity of the tank ?
|1)|| 80 gallons
||2)|| 120 gallons
|3)|| 140 gallons
||4)|| 160 gallons
|5)||None of these|Answer : 120 gallons
One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in :
|1)|| 81 min.
||2)|| 108 min.
|3)|| 144 min.
||4)|| 164 min.
|5)||None of thesae|Answer : 144 min.
Explanation : Let, the slower pipe alone will fill the tank in x minutes.
Two Pipes A and B working together can fill a cistern in 6 min. If B takes 5 min more than A to fill the cistern, then the times in which A and B will fill the cistern separately will be respectively ?
|1)|| 15 min., 20 min
||2)|| 15 min, 10 min
|3)|| 10 min, 15 min
||4)|| 25 min, 20 min
|5)||None of these|Answer : 10 min, 15 min
Two pipes can fill a tank in 10 hour and 12 hours respectively while the third can empty it in 20 hours. If all the pipes are opened together,in how many hrs the tank will be filled ?
|1)|| 7.5 hours
||2)|| 8 hours
|3)|| 8.5 hours
||4)|| 12 hours
|5)||None of these|Answer : 7.5 hours
Work done by all the tanks working together in 1 hour.
A cistern is filled in 5 hrs and it takes 6 hrs when there is a leak in its bottom. If the cistern is full, in what time shall the leak empty it ?
|1)|| 12 hour
||2)|| 15 hour
|3)|| 24 hour
||4)|| 30 hour
|5)||None of these|Answer : 30 hour
Let, the leak empties the tank in x hours.
A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. What is time for the first pipe to fill up the tank alone ?
|5)||None of these|Answer : 15hrs
Let, the first pipe can alone takes x hours to fill the tank .
Then, second and third pipes will take (x -5) and (x - 9) hours respectively .
So,(1/x) + (1/x-5) = 1/x-9.
Solving,we get x =15
Two pipes A and B can fill a tank in 15 minutes and 40 minutes respectively. Both the pipes are opened together but after 4 minutes, pipe A is turned off. What is the total time required to fill the tank ?
|1)|| 12 min 15 sec
||2)|| 15 min 30 sec
|3)|| 20 min 10 sec
||4)|| 25 min 20 sec
|5)||None of these|Answer : 25 min 20 sec
Given, the tank