Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q1. 

1)  12.5%  2)  17.5% 
3)  19%  4)  21% 
5)  None of these 
Answer : 19%
Explanation : Allegation Method:
Explanation : Allegation Method:
10% (C) x% (D)
15% (M)
(DM) = x15 (MC) = 15 10=5
So, x15 / 5 = 4/5
or x =15+4= 19%
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Q2.  When 20% of a number added to another number, the second number increases by its 50%. what is the ratio between two numbers ? 
1)  2:5  2)  5:2 
3)  2:3  4)  3:4 
5)  None of these 
Answer : 5:2
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Q3. 

1)  425  2)  480 
3)  520  4)  625 
5)  None of these 
Answer : None of these
Explanation : Let, the full mark be 100%.
Explanation : Let, the full mark be 100%.
A boy should requires marks to pass = 483 +117 = 600
So, the full mark = 600 i.e. 100%
So, the required mark for a girl should = (600/40) x 35 = 525
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Q4. 

1)  Rs.3200  2)  Rs.3126 
3)  Rs.3136  4)  Rs.3048 
5)  None of these 
Answer : Rs.3136
Explanation :
Explanation :
Let, the total amount of money with Alok be Rs.x .
x = (504 x 100)/[100  (23+33+19+16) ]= Rs. 5600
Reqd. amount of money
= ( Rs. 5600 x 56)/100= Rs. 3136
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Q5.  A shopkeeper wants to buy 600 kg watermelon,contain 99% water. On the way of shipping due to dehydration ,it contain only 98% water when it reaches at the destination. What is the present mass of the watermelon ? 
1)  294 kg  2)  300 kg 
3)  494 kg  4)  588 kg 
5)  None of these 
Answer : 300 kg
Explanation : Given, Original weight watermelon is 600 kg .
99% water i.e. 600X99/100= 594 kg and 6 kg nonwater substance.
After, dehydration, now 98% water in new content.
But nonwater substance remain constant. In the new content, water contain 2% and nonwater contain 98%.
So, 2% = 6kg.
Or 98% = (6/2) X 98 =294 kg.
Therefore, present mass = 294+6= 300kg.
Explanation : Given, Original weight watermelon is 600 kg .
99% water i.e. 600X99/100= 594 kg and 6 kg nonwater substance.
After, dehydration, now 98% water in new content.
But nonwater substance remain constant. In the new content, water contain 2% and nonwater contain 98%.
So, 2% = 6kg.
Or 98% = (6/2) X 98 =294 kg.
Therefore, present mass = 294+6= 300kg.
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Q6.  There are 480 students in a class, consists of boys and girls, appearing in an examination. 85% of girls and 70% of boys pass in that examination. How many boys pass in the examination, if over all 75% of the students pass in that examinations ? 
1)  224  2)  216 
3)  236  4)  244 
5)  None of these 
Answer : 224
Explanation : Let, boys are x. So, girls are (480 x).
Explanation : Let, boys are x. So, girls are (480 x).
Then, 70x/100 + 85(480 x)/100 = 480 (75/100)
or (70x + 408,00  85x) = 36,000
or 15x = 4800
or x =320
So, boys pass = 320 X 70/100 = 224
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Q7.  When 30% of a number added to another number , the second number is increases by 50%.What is the ratio between the first number to second number ? 
1)  3:5  2)  5:3 
3)  2:3  4)  4:5 
5)  None of these 
Answer : 5:3
Explanation : Let, two numbers are x and y respectively.
Explanation : Let, two numbers are x and y respectively.
So, 30x/100 + y = y +50y/100
or 3x = 5y
or x:y = 5:3
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Q8. 

1)  475  2)  525 
3)  545  4)  550 
5)  None of these 
Answer : 525
Explanation : Let, the Full Mark be 100%.
Explanation : Let, the Full Mark be 100%.
A boy scored 483 marks and failed by 117 marks i.e. the pass mark be 483 + 117 = 600
So, 40% = 600
or 100% = (600/40) x 100 = 1500
The minimum passing marks for the girls is = 1500 x (35/100) = 525
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Q9. 

1)  24%  2)  30% 
3)  40%  4)  45% 
5)  None of these 
Answer : 40%
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Q10. 

1)  30%  2)  26% 
3)  56%  4)  D.I 
5)  None of these 
Answer : D.I
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