Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q1.  A person sold two hens for Rs. 105 each . On one he lost 25% . On the other he gained 50% . What is the gain or loss on his total outlay ? 
1)  12.5%  2)  20% 
3)  28.3%  4)  Neither gain Nor loss 
5)  None of these 
Answer : Neither gain Nor loss
Explanation : ShortCut Method:
Explanation : ShortCut Method:
[100 x (Profit  Loss ) x 2 x Profit x Loss] / (100 + Profit ) + (100  Loss) = 0%
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Q2. 
A sells his books cost Rs.500 to B at a profit of 30%. After some period of time, B sells the same book to A at a loss of 20%. What is the total % of profit or loss in the whole trading ? 
1)  4% profit  2)  4% loss 
3)  26% profit  4)  26% loss 
5)  None of these 
Answer : 26% profit
Explanation : Let, CP of A = 100 , SP of B from A = 130 i.e. profit = 30/
Explanation : Let, CP of A = 100 , SP of B from A = 130 i.e. profit = 30/
Again , some days B sells in return to A at loss of 20% i.e. the CP of A again = 130 x (80/100) = 104
So ,in the whole trade , he gets actual profit = (304) = 26 i.e. 26%
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Q3.  Two partners invested Rs.20,000 and Rs.12,000 respectively in a business.They distribute 75% of the profit equally and distribute the rest 25% according to the ratio of their investment of capitals. If the bigger partner received Rs.400 more than the other, then what is the total profit ? 
1)  Rs.5280  2)  Rs.5600 
3)  Rs.6240  4)  Rs.6400 
5)  None of these 
Answer : Rs.6400
Explanation : Since, 75% of the profit is distributed equally ,rest 25% should be distributed according to their ratio of investment.
Explanation : Since, 75% of the profit is distributed equally ,rest 25% should be distributed according to their ratio of investment.
Actual, ratio of capital = 20000:12000 = 5:3
5/8  3/8 = 400
or 2/8 = 1/4 = 400
or 1 = 4 x 400 = 1600 i.e. 25%
So, total profit = 400 x 4 x (1/25) x 100 = 6400
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Q4.  The L.C.M and H.C.F of two numbers are 660 and 10 respectively. If the sum of the numbers is 170, what is the difference between the numbers ? 
1)  50  2)  56 
3)  60  4)  64 
5)  None of these 
Answer : 50
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Q5. 

1)  1 : 6  2)  1 : 5 
3)  1 : 25  4)  1 : 125 
5)  None of these 
Answer : 1 : 5
Explanation :
Explanation :
The volume of the larger cube = 53 = 125 cm^{3}.
The volume of each of the smaller cubes = 13 = 1 cm^{3}.
Therefore, one would get 125 smaller cubes.
The surface area of the larger cube = 6a^{2} = 6(52) = 6 25 = 150
The surface area of each of the smaller cubes = 6 (12) = 6.
Therefore, surface area of all of the 125, 1 cm^{3} cubes = 125 6 = 750.
Therefore, the required ratio = 150 : 750 = 1 : 5
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Q6. 
1)  8  2)  9 
3)  10  4)  12 
5)  None of these 
Answer : 10
Explanation :
Explanation :
Given, x^{2} + 9/x = 6x
Or x^{2}  6x = 9
Or (x3)^{2} = 0
Or x = 3
So, x^{2} + 9/x^{2 }= 10
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Q7. 

1)  221  2)  231 
3)  253  4)  0 
5)  None of these 
Answer : 253
Explanation :
Explanation :
Given, a = 4/3
Or 3a = 4
Or 3a  4 = 0
Or (3a4)^{3} = 27a^{3}  108a^{2} + 144a  64 = 0^{3}
Or 27a^{3}  108a^{2} + 144a  317 = (27a^{3}  108a^{2} + 144a 64)  153 = 0  253 =  253
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Q8.  A fort has provisions for 250 soldiers for 35 days. After 5 days a reinforcements of 25 soldiers were arrived. Again after 10 days, 25 soldiers left the fort. How long will the remaining provisions lasting ? 
1)  12  2)  16 
3)  18  4)  19 
5)  None of these 
Answer : 19
Explanation :
Explanation :
Short Cut Methods:
ND (No. of days) = N_{1}D_{1} + N_{2}D_{2} = total amount of food after 5 days.
or ( 250 X 30) = ( 250 + 25) X 10 + 250 X x
or x = 19 days .
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Q9. 

1)  33 years  2)  40 years 
3)  43 years  4)  48 years 
5)  None of these 
Answer : 43 years
Explanation :
Explanation :
Present age of C = 85 – 7 = 78 years
Present age of B = 78 – 12 = 66 years
Present age of A = 3
11 66 = 18 years
Present age of A’s father = 18 + 25 = 43 years
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Q10. 

1)  100.8 sq cm  2)  112.4 sq cm 
3)  104.2 sq cm  4)  Cannot be determined 
5)  None of these 
Answer : 100.8 sq cm
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